What is the ionic strength of 0.01 M Barium Chloride solution?
Correct answer: A. 0.03
- A. 0.03
- B. 0.02
- C. 0.04
- D. 0.01
Explanation
We know that:Ionic strength (I) = ½ (m1z1² + m2z2²)Where,m1 = concentration of Ba2+ = 0.01m2 = concentration of Cl- = 0.01 × 2 = 0.02z1 = Charged on Ba2+ = 2z2 = Charged on Cl- = -1Putting the values in the formula of ionic strength, we get:I = ½ (0.01 × 2² + 0.02 × (-1)²)= ½ (0.01 × 4 + 0.02 × 1)= ½ (0.04 + 0.02)= ½ (0.06)I = 0.03
This question appeared on the ETEA MDCAT 2010 paper, which you can sit online with every answer explained.
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