Asked in ETEA MDCAT 2015 2015

Aiman in laboratory dissolve 4g of NaOH in 250ml of water. The molarity of this solution is:

Correct answer: A. 0.4M

  • A. 0.4M
  • B. 4M
  • C. 0.2M
  • D. 0.1M

Explanation

M = 4/40 / 250/1000 = 0.4,where 4g is the amount of NaOH, 40 is the grams per mole of NaOH, 250mL is the amount of water and 1000 is the number of ml in a liter.The most common way to express solution concentration is molarity (M), which is defined as the amount of solute in moles divided by the volume of solution in liters: M = moles of solute/liters of solution.

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About Concentration Units

Concentration units express the amount of solute in a given amount of solution or solvent. Calculations cover molarity, molality, normality, mole fraction, mass percentage, volume percentage, parts per million and dilution, including the effect of temperature on volume-based units and the distinction between molarity and molality.

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