Free Satellite Motion and Orbital Velocity MCQs with Answers
26 Satellite Motion and Orbital Velocity MCQs from Physics, each with the correct answer and a written explanation of why it is correct. Free and unlimited, with no account needed.
Satellite motion uses gravitational force as the centripetal force required for circular orbit, giving relationships among orbital radius, period and orbital velocity. Questions cover geostationary conditions and weightlessness, while distinguishing orbital velocity, escape velocity and the satellite's tangential speed.
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- A. 1 hour
- B. 2 hour
- C. 12 hours
- D. 24 hours
Explanation: 24 hours: This option is correct. Geostationary communication satellites orbit the Earth at a height of about 35,786 kilometers, taking 24…
Correct answer: 24 hours- A. rotation of earth
- B. mass of body
- C. radius of earth
- D. mass of earth
Explanation: Escape velocity, Ve =√( 2GM/R) Acceleration due to gravity, g= GM/R², which is always constant.
Correct answer: radius of earth- A. stationary
- B. Rotating with the speed of earth
- C. rotating very fastly
- D. rotating very slowly
Explanation: Geostationary satellites remain at the same position with respect to the Earth, so that they scan the same place in a better way.
Correct answer: Rotating with the speed of earth- A. V ∞ r2
- B. V ∞ r
- C. V1 ∞ 1/r
- D. V ∞ 1/r2
Explanation: d) V ∞ 1/r^2 (V is proportional to 1/r^2):This option correctly represents the relationship between the speed (V) of a satellite and the…
Correct answer: V ∞ 1/r2- A. √2gR
- B. √Rg
- C. Rg/2
- D. Rg
Explanation: The force on a mass m, having an angular velocity ω orbiting in a circular path of radius R is F=mRω2.
Correct answer: √Rg- A. 1:1
- B. Square root of 3 :1
- C. 3:1
- D. 9:1
Explanation: To move in a circular orbit, gravitational force provides centripetal force.
Correct answer: Square root of 3 :1