A satellite is orbiting close to the surface of the earth, its speed is
Correct answer: B. √Rg
- A. √2gR
- B. √Rg
- C. Rg/2
- D. Rg
Explanation
The force on a mass m, having an angular velocity ω orbiting in a circular path of radius R is F=mRω2. But v=ω R, where v is the linear velocity so F=mv2/R. Equating this with the weight of the body we get, mg=mv2 /R. Or, v2 = Rg. Or, v=√(Rg)
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