Free Current Electricity MCQs with Answers

1,052 Current Electricity MCQs from Physics, each with the correct answer and a written explanation of why it is correct. Free and unlimited, with no account needed.

Steady current relates charge flow to potential difference, resistance and resistivity, including how temperature changes a conductor's resistance. Sources with internal resistance have terminal voltage below their emf when delivering current, and maximum power output occurs under a specific load condition rather than at zero resistance.

Last updated

Read the Current Electricity notesFree MDCAT chapter notes with key terms

1,052 questions · page 9 of 53

  • A. 0.04 Ω
  • B. 0.10 Ω
  • C. 0.06 Ω
  • D. 10 Ω

Explanation: The total resistance in the circuit is the sum of the ammeter's resistance (R) and the cell's internal resistance (r).

Correct answer: 0.06 Ω
  • A. 1%
  • B. 0.5%
  • C. 2%
  • D. 0.25%

Explanation: Power dissipated is given by P = I²R. For small percentage changes, the percentage change in power is approximately twice the percentage…

Correct answer: 1%
  • A. They have equal currents through them
  • B. The resistance of the filaments in both the bulbs is same through them
  • C. The resistance of the filament in 40 watt bulb is more than the resistance in 100 watt bulb
  • D. The resistance of the filament in 100 watt bulb is more than the resistance in 40 watt bulb

Explanation: Since Power P = V²/R, resistance R = V²/P. Both bulbs are rated for the same voltage (200V).

Correct answer: The resistance of the filament in 40 watt bulb is more than the resistance in 100 watt bulb
  • A. Halved
  • B. Four times
  • C. One-fourth
  • D. Doubled

Explanation: When the coil is cut in half, its resistance is halved (R' = R/2). Since it's connected to the same voltage source, the power P = V²/R…

Correct answer: Doubled
  • A. 64 W
  • B. 100 W
  • C. 72 W
  • D. 90 W

Explanation: First, find the bulb's resistance from its rating: R = V²/P = (200V)² / 100W = 400 Ω.

Correct answer: 64 W
  • A. 200 J
  • B. 800 J
  • C. 400 J
  • D. 40 J

Explanation: The power converted into light is half the total power, so Plight = 0.5 × 40 W = 20 W.

Correct answer: 200 J
  • A. 200-ohm
  • B. 50 ohm
  • C. 400 ohm
  • D. 5 ohm

Explanation: From the power formula P = V²/R, we can solve for resistance: R = V²/P. R = (200 V)² / 100 W = 40000 / 100 = 400 Ω.

Correct answer: 400 ohm
  • A. 25 W
  • B. 60 W
  • C. 50 W
  • D. 40 W

Explanation: All bulbs are designed for the same voltage (like in a standard household), and resistance is R = V²/P.

Correct answer: 60 W
  • A. Ω-m²
  • B. (Ω-m)-1
  • C. Ω-m
  • D. (Ω-m)-2

Explanation: Resistivity (ρ) is defined by the formula R = ρL/A. Rearranging for ρ gives ρ = RA/L.

Correct answer: Ω-m
  • A. 120 A
  • B. 120 x 10^3A
  • C. 120 x 10^-3 A
  • D. None

Explanation: The current (I) can be calculated using the equation V = IR(120) = (1000)(I)120/1000 = II = 120 times 10-3 A.

Correct answer: 120 x 10^-3 A
  • A. 45 W
  • B. 90 W
  • C. 290 W
  • D. 360 W

Explanation: First, convert the current to Amperes: I = 500 mA = 0.5 A. Use the power formula P = I²R. P = 0.5 A² × 180 Ω = 0.25 × 180 = 45 W.

Correct answer: 45 W
  • A. 5V
  • B. 1.2V
  • C. 0.9V
  • D. 0.6V

Explanation: First, find the total current in the circuit: I = E / (Rext + rint) = 1.5V / (3.0Ω + 2.0Ω) = 0.3 A.

Correct answer: 0.9V
  • A. 22 kW
  • B. 22 W
  • C. 2.2 kW
  • D. 2.2 W

Explanation: The rate of energy transfer is power (P). The formula for electrical power is P = VI. P = (220 V) × (0.1 A) = 22 W.

Correct answer: 22 W
  • A. 4R
  • B. 3R
  • C. 2R
  • D. R

Explanation: The resistance of a wire is given by R∝L/A, and the cross-sectional area is proportional to the square of the diameter, A∝d².

Correct answer: 2R
  • A. 16R
  • B. 4R
  • C. 1/16 R
  • D. 1/4R

Explanation: Assuming the volume of the wire is conserved during compression, if the radius doubles (r' = 2r), the area becomes 4 times larger (A' =…

Correct answer: 1/16 R
  • A. Filament bulb
  • B. Semiconductor diode
  • C. Transistor
  • D. Copper wire

Explanation: An Ohmic device has a constant resistance, meaning its V-I graph is a straight line.

Correct answer: Copper wire
  • A. Non-linear
  • B. Curve
  • C. Linear
  • D. Curvilinear

Explanation: For many metallic conductors, the relationship between resistance and temperature is approximately linear over a wide range, including…

Correct answer: Linear
  • A. 11Ω
  • B. 121Ω
  • C. 20Ω
  • D. 200Ω

Explanation: From the power formula P = V²/R, we can rearrange to find the resistance: R = V²/P. R = (110 V)² / 100 W = 12100 / 100 = 121 Ω.

Correct answer: 121Ω
  • A. Double
  • B. Four times
  • C. One half
  • D. One fourth

Explanation: Resistance is given by R = ρL/A. The new resistance R' will be R' = ρ(2L) / (A/2) = 4(ρL/A) = 4R. The resistance becomes four times larger.

Correct answer: Four times
  • A. Temperature and nature of material
  • B. Length
  • C. Area
  • D. All

Explanation: Conductivity, like its inverse resistivity, is an intrinsic property of a material.

Correct answer: Temperature and nature of material