Free Measurement and Instrumentation MCQs with Answers

156 Measurement and Instrumentation MCQs from Electrical Engineering, each with the correct answer and a written explanation of why it is correct. Free and unlimited, with no account needed.

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156 questions · page 4 of 8

  • A. to the supply side of the current coil
  • B. to the load side of the current coil
  • C. in any of the two meters at connection
  • D. none of the above

Explanation: In a low-power-factor wattmeter, the pressure coil is connected on the load side of the current coil to reduce the effect of the…

Correct answer: to the load side of the current coil
  • A. almost zero
  • B. low
  • C. high
  • D. none of the above

Explanation: The moving-coil or pressure-coil circuit of a dynamometer wattmeter must have high resistance so that its current is small and the…

Correct answer: high
  • A. in series with current coil
  • B. in parallel with current coil
  • C. in series with pressure coil
  • D. in parallel with pressure coil

Explanation: The compensating coil is connected in series with the pressure coil so that its magnetic effect compensates for the pressure-coil…

Correct answer: in series with pressure coil
  • A. both D.C. and A.C.
  • B. D.C. only
  • C. A.C. only
  • D. any of the above

Explanation: A dynamometer wattmeter uses the interaction of magnetic fields produced by its fixed and moving coils, a principle that works with either…

Correct answer: both D.C. and A.C.
  • A. series
  • B. parallel
  • C. series-parallel
  • D. none of the above

Explanation: A voltmeter is made by connecting a high-value multiplier resistor in series with the meter coil, limiting the current to a safe value.

Correct answer: series
  • A. moving iron instrument
  • B. electrostatic instrument
  • C. thermocouple instrument
  • D. none of the above

Explanation: A thermocouple instrument is suitable for high-frequency current because its thermal action responds to the heating effect and can…

Correct answer: thermocouple instrument
  • A. friction compensation
  • B. creep compensation
  • C. braking torque
  • D. none of the above

Explanation: The shading bands on an energy meter adjust the phase and magnitude of the shunt-magnet flux at light load, producing a compensating…

Correct answer: friction compensation
  • A. Kelvin's double bridge
  • B. Wheat stone bridge
  • C. Meggar
  • D. None of the above

Explanation: A Megger, or insulation-resistance tester, is designed to measure very high resistances by applying a comparatively high test voltage.

Correct answer: Meggar
  • A. 6 V
  • B. 12 V
  • C. 40 V
  • D. 100 V

Explanation: A Megger contains a hand-driven or electronic high-voltage source, and traditional instruments commonly provide test voltages around 100 V…

Correct answer: 100 V
  • A. short-circuited
  • B. all right
  • C. faulty

Explanation: A good capacitor initially draws charging current, so the ohmmeter shows low resistance; as the capacitor charges, the current falls and…

Correct answer: all right
  • A. a D.C. potentiometer directly
  • B. a D.C. potentiometer in conjunction with a standard resistance
  • C. a D.C. potentiometer in conjunction with a volt ratio box
  • D. none of the above

Explanation: A potentiometer measures voltage directly, so current is found by passing it through a known standard resistance and measuring the voltage…

Correct answer: a D.C. potentiometer in conjunction with a standard resistance
  • A. Small range moving coil voltmeter
  • B. D.C. potentiometer
  • C. Small range thermocouple voltmeter
  • D. None of the above

Explanation: A DC potentiometer is a null-type instrument, so it draws no current from the source at balance and avoids loading errors.

Correct answer: D.C. potentiometer
  • A. necessary to standardise the potentiometer
  • B. not necessary to standardise the potentiometer
  • C. necessary to use a volt ratio box in conjunction with the potentiometer
  • D. none of the above

Explanation: In resistance measurement by comparing potentiometer balance lengths, the potentiometer constant and working current cancel in the ratio…

Correct answer: not necessary to standardise the potentiometer
  • A. battery
  • B. permanent magnet D.C. generator
  • C. AC. generator
  • D. any of the above

Explanation: A conventional hand-driven megger uses a permanent-magnet DC generator to produce its test voltage, avoiding dependence on an external…

Correct answer: permanent magnet D.C. generator
  • A. D.C. voltmeter
  • B. Ammeter and a known resistance
  • C. D.C. potentiometer
  • D. None of the above

Explanation: A DC potentiometer measures emf under virtually zero current, so there is no internal-resistance voltage drop and the true open-circuit…

Correct answer: D.C. potentiometer
  • A. moving iron instrument
  • B. moving coil instrument
  • C. dynamometer instrument
  • D. none of the above

Explanation: An ohmmeter commonly uses a permanent-magnet moving-coil movement with an internal battery and resistors; the pointer deflection is…

Correct answer: moving coil instrument
  • A. unity
  • B. 0.8 lagging
  • C. 0.8 leading
  • D. zero

Explanation: For two-wattmeter measurement, equal readings require cos(30°−φ) = cos(30°+φ), which gives φ = 0° for a normal balanced load.

Correct answer: unity
  • A. An operating torque system
  • B. A braking device
  • C. Revolution registering device
  • D. All of the above

Explanation: A motor meter needs an operating torque to drive its mechanism, a braking device to control speed, and a revolution-registering device to…

Correct answer: All of the above
  • A. an indicating instrument
  • B. a recording instrument
  • C. an integrating instrument
  • D. none of the above

Explanation: A household energy meter accumulates electrical energy over time, usually in kilowatt-hours, rather than merely showing an instantaneous…

Correct answer: an integrating instrument
  • A. secondary instrument
  • B. absolute instrument
  • C. recording instrument
  • D. integrating instrument

Explanation: An ammeter is calibrated against a standard and is used to measure current, so it is a secondary instrument.

Correct answer: secondary instrument