Free Electrical Machines MCQs with Answers

1,061 Electrical Machines MCQs from Electrical Engineering, each with the correct answer and a written explanation of why it is correct. Free and unlimited, with no account needed.

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  • A. poor insulation
  • B. Overload
  • C. loose connections
  • D. Core saturation

Explanation: A saturated core draws a nonsinusoidal magnetizing current, and nonsinusoidal current contains harmonics.

Correct answer: Core saturation
  • A. low power factor wattmeter
  • B. unity power factor wattmeter
  • C. frequency meter
  • D. any type of wattmeter

Explanation: In the open-circuit test, the wattmeter reading is mainly the iron loss, while the power factor is very low because the exciting current…

Correct answer: low power factor wattmeter
  • A. Core loss
  • B. Friction loss
  • C. Eddy current loss
  • D. Hysteresis loss

Explanation: A transformer has no rotating mechanical parts, so it has no friction loss even at full load.

Correct answer: Friction loss
  • A. capacitive only
  • B. inductive only
  • C. inductive or resistive
  • D. none of the above

Explanation: A leading, usually capacitive, load can make the reactive voltage-drop component oppose the resistive drop, producing negative regulation.

Correct answer: capacitive only
  • A. low voltage side of high kVA transformers
  • B. high frequency transformers
  • C. high voltage side of small capacity transformers
  • D. high voltage side of high kVA rating transformers

Explanation: Helical windings are suited to low-voltage, high-current windings because their construction provides good mechanical strength and…

Correct answer: low voltage side of high kVA transformers
  • A. Core insulation voltage test
  • B. Impedance test
  • C. Radio interference test
  • D. Polarity test

Explanation: Radio interference testing is generally a special test performed when specified, not part of the standard routine tests applied to every…

Correct answer: Radio interference test
  • A. leading power factor
  • B. lagging power factor
  • C. unity power factor
  • D. zero power factor

Explanation: The resistive voltage drop and reactive voltage drop can cancel when the load power factor is leading, giving zero regulation.

Correct answer: leading power factor
  • A. value of transformation ratio remains constant
  • B. permeability of transformer core remains constant
  • C. core flux remains practically constant
  • D. primary voltage remains constant
  • E. secondary voltage remains constant

Explanation: With rated voltage and frequency held constant, the core flux is approximately constant from no load to full load.

Correct answer: core flux remains practically constant
  • A. flux density remains unaffected
  • B. iron losses are reduced
  • C. core flux density is reduced
  • D. core flux density is increased

Explanation: Transformer flux is approximately proportional to voltage divided by frequency.

Correct answer: core flux density is increased
  • A. Low hysteresis loss
  • B. High permeability
  • C. High thermal conductivity
  • D. Adequate mechanical strength

Explanation: Low hysteresis loss, high permeability, and adequate mechanical strength are important core-material properties.

Correct answer: High thermal conductivity
  • A. load current
  • B. load current and voltage
  • C. load current, voltage and frequency
  • D. load current, voltage, frequency and power factor

Explanation: Load current produces the ampere-turns that establish leakage flux, so leakage flux increases approximately with load current.

Correct answer: load current
  • A. no losses and magnetic leakage
  • B. interleaved primary and secondary windings
  • C. a common core for its primary and secondary windings
  • D. core of stainless steel and winding of pure copper metal
  • E. none of the above

Explanation: An ideal transformer assumes zero winding and core losses, infinite permeability, and no leakage flux.

Correct answer: no losses and magnetic leakage
  • A. Frequency
  • B. Voltage
  • C. Current
  • D. Any of the above

Explanation: An ordinary transformer changes voltage and current according to its turns ratio, but it does not change the supply frequency.

Correct answer: Frequency
  • A. Conservator
  • B. Breather
  • C. Bushings
  • D. Buchholz relay

Explanation: The conservator provides space for transformer oil to expand and contract as its temperature changes.

Correct answer: Conservator
  • A. small air gap
  • B. large leakage flux
  • C. laminated silicon steel core
  • D. fewer rotating parts

Explanation: A transformer core has a very small air gap and high permeability, so only a small magnetising current is needed to establish the flux.

Correct answer: small air gap
  • A. electrical fault inside the transformer itself
  • B. electrical fault outside the transformer in outgoing feeder
  • C. for both outside and inside faults
  • D. none of the above

Explanation: A Buchholz relay is installed in the oil pipe between the transformer tank and conservator, so it detects gas formation and oil surges…

Correct answer: electrical fault inside the transformer itself
  • A. short-circuiting of the secondaries
  • B. power factor of one of the transformers is leading while that of the other lagging
  • C. transformers having higher copper losses will have negligible core losses
  • D. loading of the transformers not in proportion to their kVA ratings

Explanation: When parallel transformers have unequal percentage impedances, the lower-impedance transformer takes a greater share of the load.

Correct answer: loading of the transformers not in proportion to their kVA ratings
  • A. the current on secondary side is negligible
  • B. the voltage on secondary side does not vary
  • C. the voltage applied on primary side is low
  • D. full-load current is not supplied to the transformer

Explanation: In the short-circuit test, only a small primary voltage is needed to circulate rated current because the winding impedance is low.

Correct answer: the voltage applied on primary side is low
  • A. Hysteresis losses are reduced
  • B. Saving in winding material
  • C. Copper losses are negligible
  • D. Eddy losses are totally eliminated

Explanation: An autotransformer uses part of the same winding for both primary and secondary, so less copper and conductor material are required than…

Correct answer: Saving in winding material
  • A. no-load
  • B. half-load
  • C. near full-load
  • D. 10% overload

Explanation: Power transformers operate near full load for much of their service, so they are designed for maximum efficiency near full-load…

Correct answer: near full-load