Free Electrical Machines MCQs with Answers

1,061 Electrical Machines MCQs from Electrical Engineering, each with the correct answer and a written explanation of why it is correct. Free and unlimited, with no account needed.

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1,061 questions · page 42 of 54

  • A. increase in armature current
  • B. increase in flux
  • C. decrease in reactance
  • D. decrease in back emf

Explanation: An increased load raises armature current, increasing the armature resistance drop.

Correct answer: decrease in back emf
  • A. runs as a generator
  • B. does not run as a generator
  • C. also runs as a motor comes to stop after sometime

Explanation: When the second DC motor is excited and mechanically driven by the first motor, its armature conductors cut magnetic flux and generate…

Correct answer: runs as a generator
  • A. reducing the field current
  • B. decreasing the armature current
  • C. increasing the armature current
  • D. increasing the excitation current
  • E. none of the above methods

Explanation: Speed of a shunt motor can be increased above its normal value by field weakening.

Correct answer: reducing the field current
  • A. the field
  • B. the armature
  • C. the brushes
  • D. the commutator

Explanation: Iron losses are caused by alternating magnetisation of the iron core, producing hysteresis and eddy-current losses.

Correct answer: the armature
  • A. Series motor
  • B. Shunt motor
  • C. Cumulatively compounded motor
  • D. Differentially compounded motor

Explanation: A series motor has the strongest automatic speed response to load changes: increased load current strengthens its flux and reduces speed…

Correct answer: Series motor
  • A. series motor
  • B. shunt motor
  • C. compound motor
  • D. any of the above

Explanation: A compound motor is suitable for a load that varies from nearly zero to a short-duration peak because it combines good no-load speed…

Correct answer: compound motor
  • A. series motor
  • B. shunt motor
  • C. compound motor
  • D. any of the above

Explanation: A series motor is suitable when the load remains present but periodically reaches a high peak, because its series field provides high…

Correct answer: series motor
  • A. drum type controller is used
  • B. three point starter is used
  • C. four point starter is used
  • D. all above can be used

Explanation: A drum controller is designed for frequent starting, stopping, reversing and speed control of comparatively large motors.

Correct answer: drum type controller is used
  • A. self-induced e.m.f.
  • B. mutually induced e.m.f.
  • C. back e.m.f
  • D. none of the above

Explanation: As a motor armature rotates, it cuts the magnetic flux and generates an e.m.f. opposing the applied voltage, so it is called back e.m.f.

Correct answer: back e.m.f
  • A. a stronger commutating field is needed at low speed than at high speed
  • B. a weaker commutating field is needed at low speed than at high speed
  • C. same commutating field is needed at low speed than at high speed
  • D. none of the above is correct

Explanation: At higher speed, commutation occurs in less time, so a stronger interpole or commutating field is needed to reverse armature current…

Correct answer: a weaker commutating field is needed at low speed than at high speed
  • A. Plugging
  • B. Regenerative braking
  • C. Rheostatic braking
  • D. None of the above

Explanation: Plugging applies a reverse torque and brings an elevator to rest quickly, which is important for accurate stopping at floors.

Correct answer: Plugging
  • A. Shunt motors
  • B. Series motors
  • C. Compound motors
  • D. All of the above

Explanation: Dynamic braking converts the motor into a generator and dissipates the generated energy in a resistance.

Correct answer: All of the above
  • A. motor is run as a generator
  • B. motor is reversed in direction
  • C. motor is run at reduced speed

Explanation: In rheostatic or dynamic braking, the supply is disconnected and the running motor is connected as a generator feeding a braking resistor.

Correct answer: motor is run as a generator
  • A. no-load
  • B. part load
  • C. full-load
  • D. overload

Explanation: Hopkinson’s test is a regenerative back-to-back test in which one machine operates as a motor and the other as a generator, normally at…

Correct answer: full-load
  • A. Swinburne's test
  • B. Hopkinson's test
  • C. Field test
  • D. Brake test

Explanation: Field’s test is suitable for two similar large D.C. series motors because the machines can be mechanically coupled and tested under load…

Correct answer: Field test
  • A. iron losses
  • B. line losses
  • C. sparking
  • D. corona losses

Explanation: Locating generators near load centres shortens the transmission and distribution lines, thereby reducing I²R losses in the line…

Correct answer: line losses
  • A. yoke
  • B. commutator
  • C. armature conductors
  • D. armature rotor

Explanation: Iron losses consist of hysteresis and eddy-current losses, and they occur mainly in the laminated armature core as it rotates through the…

Correct answer: armature rotor
  • A. full-load
  • B. rated r.p.m.
  • C. rated voltage
  • D. all of the above

Explanation: A DC generator is normally designed so that its highest efficiency occurs close to full-load operation, where its fixed losses and…

Correct answer: full-load
  • A. eddy current losses = stray losses
  • B. hysteresis losses = eddy current losses
  • C. copper losses = 0
  • D. variable losses = constant losses

Explanation: Maximum efficiency occurs when the variable losses, chiefly armature copper loss, equal the constant losses, such as iron, friction and…

Correct answer: variable losses = constant losses
  • A. 100 W
  • B. 500 W
  • C. 1000 W
  • D. 1500 W

Explanation: A well-designed 10 kW generator commonly has total losses of roughly 5% of its rating, giving about 0.05 × 10,000 = 500 W.

Correct answer: 500 W