Free Standard Temperature and Pressure MCQs with Answers
27 Standard Temperature and Pressure MCQs from Chemistry, each with the correct answer and a written explanation of why it is correct. Free and unlimited, with no account needed.
Standard temperature and pressure provide reference conditions for gas calculations: 0°C or 273 K and, in the usual school convention, 1 atm pressure. Questions use these conditions to relate pressure, volume, temperature and amount of gas, including the molar volume of an ideal gas, about 22.4 dm³.
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27 questions · page 2 of 2
- A. 20.414 dm3
- B. 22.414 dm3
- C. 22.414 cm3
- D. 23.414 dm3
Explanation: A is incorrect as the given volume is not correct under standard conditions.B is correct as the given volume (22.4 dm3) is correct under…
Correct answer: 22.414 dm3- A. 22.41 dm3
- B. 44.82 dm3
- C. 64.82 dm3
- D. 2.241 dm3
Explanation: To find the volume of a gas, we use the formula: Moles = Volume of gas / 22.
Correct answer: 22.41 dm3- A. N2
- B. H2
- C. O2
- D. Number of molecules are equal
Explanation: The number of molecules is given by the formula:Number of molceules = moles x avogadros constantSince all of the given elements have the…
Correct answer: Number of molecules are equal- A. 22.4 dm3
- B. 2.24 dm3
- C. 4.48 dm3
- D. 44.8 dm3
Explanation: Moles of N 2 =2.8/28=0.1 moleAtS.T.P: mole→22.4 L ∴0.1 mole →2.24 L=2240 ml=2240cc=2.24 dm3
Correct answer: 2.24 dm3- A. 22.4 dm3
- B. 2.24 dm3
- C. 11.2 dm3
- D. 16.0 dm3
Explanation: At STP, one mole of any ideal gas occupies 22.4 dm3. The molar mass of oxygen (O2) is 32 g/mol.
Correct answer: 2.24 dm3- A. 2.24dm3
- B. 1.12dm3
- C. 22.4dm3
- D. 24dm3
Explanation: To find the volume of 1.6 g of O2 at STP (Standard Temperature and Pressure), we can use the ideal gas law equation: PV = nRT.
Correct answer: 2.24dm3- A. 1.12 dm3
- B. 2.24 dm3
- C. 22.4 dm3
- D. 24 dm3
Explanation: Option B is correct. The volume occupied by 3.2 g of oxygen gas at STP is 2.24 dm3.
Correct answer: 2.24 dm3