Free Fundamental Concepts of Chemistry MCQs with Answers
894 Fundamental Concepts of Chemistry MCQs from Chemistry, each with the correct answer and a written explanation of why it is correct. Free and unlimited, with no account needed.
Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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Read the Fundamental Concepts of Chemistry notesFree MDCAT chapter notes with key terms894 questions · page 35 of 45
- A. 32 g
- B. 41.2 g
- C. 82.4 g
- D. 156 g
Explanation: The correct answer is 82.4 g. The reaction between the alcohol ROH and CH3MgI produces CH4 as a gas.
Correct answer: 82.4 g- A. 3.6 cm3
- B. 60 cm3
- C. 0.6 cm3
- D. 0.06 cm3
Explanation: At 100°C and 1 atm, the volume occupied by water molecules in 1 liter of steam is 0.6 cm³.
Correct answer: 0.6 cm3- A. C2H2
- B. C2H4
- C. C6H6
- D. C8H8
Explanation: PV = nRT n = PV/RT = 1 x 0.224 L / 0.08206 x 273 n = 0.001 mole Molar mass = 0.078/0.001 = 78 g Empirical formula = CH Mass according to…
Correct answer: C6H6- A. 0.4 N
- B. 0.5 N
- C. 1.05 N
- D. 0.15 N
Explanation: Following is the solution to this question:
Correct answer: 0.5 N- A. 16/N
- B. 32/N
- C. 16 N
- D. 32 N
Explanation: To find the weight of one atom of the diatomic gas, you can use the ideal gas law: PV = nRT Where: P = Pressure (2 atm) V = Volume (350 mL…
Correct answer: 16/N- A. 440gm
- B. 44gm
- C. 0.1mole
- D. 880gm
Explanation: The amount of CO2 present in the mixture is 440 gm.
Correct answer: 440gm- A. More than 100
- B. 3
- C. 2
- D. Equal to 100
Explanation: There are 2 types of fundamental particles present in the nucleus i.c. proton & neutron.
Correct answer: 2- A. 0.693/k
- B. 0.693/2k
- C. log2/k
- D. In2/k
Explanation: Half life is inversely proportional in second order reaction.
Correct answer: 0.693/k- A. 100°C, 1 atm
- B. 298 K, 1 atm
- C. 273K, 760 mmHg
- D. 0°C, 760 cmHg
Explanation: The values of temperature and pressure at standard conditions (STP) are: Temperature: 0 degrees Celsius (273.15 K) Pressure: 1 atm…
Correct answer: 273K, 760 mmHg- A. 6.02 x 10^23
- B. 16 x 10^23
- C. 1.6 x 10^23
- D. 6.02 x 1 022
Explanation: The molar mass of methane is 16 g/mol, so 1.6 g of methane contains 1.6/16 = 0.1 moles of methane.There are 10 electrons in each methane…
Correct answer: 6.02 x 10^23- A. 5
- B. 10
- C. 10.5
- D. 15
- E. 25
Explanation: Consider that no. of moles of reactants = volume of the reactants. As the molar ratio between C3H6 and O2 is 1:5, the volume ratio is also…
Correct answer: 25- A. Anemic
- B. Cannot be determined
- C. Normal
- D. Polycythemic
Explanation: To determine whether Jimmy is anemic or not, we need to calculate his hemoglobin count based on the given red blood cell count.One red…
Correct answer: Anemic- A. 22.4 dm3
- B. 1.12 dm3
- C. 11.2 dm3.
- D. 1.4 dm3
Explanation: To find the moles of nitrogen, it is necessary to use the idea of molar volume Mass of N2 = 1.4 g Moles of N2 = 1.4g / 28g per mole = 0.05…
Correct answer: 1.12 dm3- A. 1
- B. 18
- C. 36
- D. 55.5
Explanation: Molarity is defined as the number of moles of solute per liter of solution.
Correct answer: 55.5695. A polymer of empirical formula CH2 has molar mass of 28000g mol-1. Its molecular formula will be
- A. 100 times that of its empirical formula
- B. 200 times that of its empirical formula
- C. 500 times that of its empirical formula
- D. 2000 times that of its empirical formula
Explanation: The empirical mass of CH4 is 12+2=14g. Dividing molar mass by observed mass will give us the answer: 28000/14=2000 times.
Correct answer: 2000 times that of its empirical formula- A. 6.02 x 10^24
- B. 6.02 x 10^23
- C. 3.01 x 10^24
- D. 3.01 x 10^23
Explanation: Water has a mass of 18g(16+2). So,9g of ice(H2O) means 0.5 mol. 1 mol has a 6.02x1023 number of molecules, so 0.5 mol will have a…
Correct answer: 3.01 x 10^23697. 1.2 g of Mg was dropped in 100 ml of 0.1 M HCl solution. Calculate the volume of H2 obtained by STP.
- A. 0.8 L
- B. 0.5 L
- C. 0.4 L
- D. 0.112 L
Explanation: The working for the above question is as following:
Correct answer: 0.112 L- A. 3.6 cm3
- B. 60 cm3
- C. 0.6 cm3
- D. 0.06 cm3
Explanation: Following is the solution to this question:
Correct answer: 0.6 cm3- A. C12O9
- B. C4O3
- C. C3O4
- D. C9O12
Explanation: Following is the solution to this question:
Correct answer: C12O9- A. 0.2
- B. 0.5
- C. 0.3
- D. 0.1
Explanation: Following is the solution to this question:
Correct answer: 0.1