Total no. of electrons present in 1.6g of methane:
Correct answer: A. 6.02 x 10^23
- A. 6.02 x 10^23
- B. 16 x 10^23
- C. 1.6 x 10^23
- D. 6.02 x 1 022
Explanation
The molar mass of methane is 16 g/mol, so 1.6 g of methane contains 1.6/16 = 0.1 moles of methane.There are 10 electrons in each methane molecule, so there are 0.1 * 10 = 1.0 moles of electrons in 1.6 g of methane.Avogadro's number is the number of atoms in a mole of a substance, and it is equal to 6.022 x 1023 atoms/mol. So, there are 1.0 * 6.022 x 1023= 6.022 x 1023 electrons in 1.6 g of methane.Therefore, there are 6.022 x 1023 electrons present in 1.6 g of methane.
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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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