Free Electronic Structure of d-Block Elements MCQs with Answers

154 Electronic Structure of d-Block Elements MCQs from Chemistry, each with the correct answer and a written explanation of why it is correct. Free and unlimited, with no account needed.

The electronic structure of d-block elements covers the filling of the (n-1)d and ns orbitals, general electronic configurations, and the exceptions shown by chromium and copper. It explains how partially filled d orbitals produce variable oxidation states, coloured ions, magnetic behaviour and complex formation, while distinguishing transition elements from elements with completely filled d subshells.

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154 questions · page 8 of 8

  • A. +2
  • B. +5
  • C. +7
  • D. +8

Explanation: The highest oxidation state of manganese in its compounds is +7. In this oxidation state, manganese forms compounds like potassium…

Correct answer: +7
  • A. 1s2 2s2 2p6 3s2 3p6 3d8 4s2
  • B. 1s2 2s2 2p6 3s2 3p6 3d7 4s2 4p1
  • C. 1s2 2s2 2p6 3s2 3p6 3d6 4s2 4p2
  • D. 1s2 2s2 2p6 3s2 3p6 3d6 4s1 4p3

Explanation: The correct electronic configuration for Nickel (28) is 1s2 2s2 2p6 3s2 3p6 3d8 4s2.

Correct answer: 1s2 2s2 2p6 3s2 3p6 3d8 4s2
  • A. Unpaired d Electrons
  • B. Unpaired p electrons
  • C. Unpaired f electrons
  • D. Paired up d electrons

Explanation: Transition elements exhibit variable oxidation states due to the involvement of their ns and (n-1) d electrons.

Correct answer: Unpaired d Electrons
  • A. Two of its atoms
  • B. Three of its atoms
  • C. Four of its atoms
  • D. Six of its atoms

Explanation: When this ion bonds to a metal atom, the two N atoms, and four of the O atoms, are used.

Correct answer: Six of its atoms
  • A. Open hearth furnace
  • B. Reverberatory furnace
  • C. Bessemer converter
  • D. Blast furnace

Explanation: A puddling furnace is used which is a type of an open hearth furnace, it is constructed to pull hot air over the iron without the fuel…

Correct answer: Open hearth furnace
  • A. Iron
  • B. Nickel
  • C. Cobalt
  • D. Barium

Explanation: Barium is not a ferromagnetic material. Ferromagnetic materials have a strong magnetic response to an external magnetic field, and they…

Correct answer: Barium
  • A. [Cr (H2 O)5Cl] Cl3
  • B. [Cr (H2 O)5Cl] Cl2
  • C. [Cr (H2 O)5 Cl2] Cl
  • D. [Cr (H2 O)5 Cl3] Cl

Explanation: 'Chloro' in the name suggests the presence of one chlorine in the ligand complex, Penta (5) aqua (H2O) shows that there are five water…

Correct answer: [Cr (H2 O)5Cl] Cl2
  • A. Cr2+, Co2+, Cu2+
  • B. Cu2+, Zn2+, Ti4+
  • C. Ti3+, Zn2+, Cu2+
  • D. Cr3+, Ti4+, Cu2+

Explanation: The correct answer is Option A: Cr2+, Co2+, Cu2+. These transition metal ions possess unpaired d-electrons, allowing for d-d electronic…

Correct answer: Cr2+, Co2+, Cu2+
  • A. [Cu(H2O)2 (NH3)2 (OH)2]
  • B. [Cu(NH3)4 (OH)2]
  • C. [Cu (NH3)4 (H2O)2]2+
  • D. [Cu (NH3)3 (H2O)3]2+

Explanation: Ammonia acts as a ligand in this reaction, replacing water molecules in the coordination sphere of the copper ion, forming…

Correct answer: [Cu (NH3)4 (H2O)2]2+
  • A. [Co(en)2Cl2]
  • B. [Co(en)2Cl2]2-
  • C. [Co(ebn)2Cl2]1-
  • D. [Co(en)2Cl2]1+

Explanation: The correct formula for Dichloro-Bis-ethylenediamine cobalt (II) is [Co(en)2Cl2].

Correct answer: [Co(en)2Cl2]
  • A. Blue
  • B. Greenish blue
  • C. Bluish green
  • D. Colourless

Explanation: Transition elements exhibit color due to d-d transition. d-d transition is possible only when the d subshell has unpaired electrons.

Correct answer: Colourless
  • A. Cr
  • B. Mn
  • C. Zn
  • D. Fe

Explanation: Zinc (Zn) is considered a non-typical transition element because it does not exhibit typical transition metal properties like variable…

Correct answer: Zn
  • A. 3d
  • B. 4d
  • C. 5d
  • D. 6d

Explanation: In the fourth transition series, the subshell that is in the process of completion is the 3d subshell.

Correct answer: 3d
  • A. Fe
  • B. Co
  • C. Sb
  • D. Ni

Explanation: Antimony (Sb) is not ferromagnetic. It is considered a diamagnetic material, which means it is weakly repelled by both poles of a magnet…

Correct answer: Sb