All Free Chemistry MCQs with Answers

Every Chemistry question in the bank, across all chapters, each with the correct answer and a written explanation. Free and unlimited, with no account needed.

13,720 questions · page 569 of 686

  • A. H2O is the reducing agent
  • B. H2O is the oxidising agent
  • C. Carbon is the oxidising agent
  • D. Oxidation-reaction does not occur

Explanation: In the given reaction, H2O is reduced to H2, meaning it gains hydrogen atoms.

Correct answer: H2O is the oxidising agent
  • A. Cu + HNO3 → Cu(NO3)2 + NO + H2O
  • B. I2 + OH- → IO- + I- + H2O
  • C. Cl2 + I2 → 2ClI
  • D. Zn + 2HCl → ZnCl2 + H2

Explanation: In a disproportionation reaction, a single element in one oxidation state is simultaneously oxidized and reduced to form two different…

Correct answer: I2 + OH- → IO- + I- + H2O
  • A. A
  • B. B
  • C. C
  • D. D

Explanation: Cu + H2SO4 → CuO + H2O + SO2 (H2SO4 act as oxidant) CuO + H2SO4 → CuSO4 + H2O (H2SO4 act as acid)

Correct answer: C
  • A. Both half-cell reactions take place simultaneously
  • B. Of resistance of the wire
  • C. A reaction does not take place on its own
  • D. None of the above

Explanation: It is impossible to measure the actual voltage of any half-cell by itself because a reaction does not take place on its own.

Correct answer: A reaction does not take place on its own
  • A. 4.305 amp
  • B. 17.22 amp
  • C. 8.61 amp
  • D. 2.1525 amp

Explanation: The correct answer is 8.61 amp. To determine this, we utilize Faraday's laws of electrolysis, which state that the amount of substance…

Correct answer: 8.61 amp
  • A. Less than anode
  • B. The same as anode
  • C. More than anode
  • D. Always zero

Explanation: At cathode reduction takes place hence it has greater Eered than anode.

Correct answer: More than anode
  • A. A
  • B. B
  • C. C
  • D. D

Explanation: The correct answer is Option C. Copper (Cu) is below hydrogen in the electrochemical series, which means it cannot displace hydrogen from…

Correct answer: C
  • A. A
  • B. B
  • C. C
  • D. D

Explanation: The reaction MgO + 2H2O → MgCl2 + 2H2O is a double displacement reaction.

Correct answer: B
  • A. Anode
  • B. Cathode
  • C. At the surface of the electrolyte
  • D. None of these

Explanation: In electrochemical cells, reduction occurs at the cathode, which is the electrode where electrons are gained by the chemical species.

Correct answer: Cathode
  • A. Option A
  • B. Option B
  • C. Option C
  • D. Option D

Explanation: Following is the solution to this question:

Correct answer: Option B
  • A. VO2+ → V2O3
  • B. Na → Na+
  • C. CrO4-2 → Cr2O72-
  • D. Zn2+ → Zn

Explanation: 2Cr6+ → Cr26+ ; Neither oxidation nor reduction.

Correct answer: CrO4-2 → Cr2O72-
  • A. The law is valid at infinite dilution
  • B. The law is valid for weak electrolytes only
  • C. The basis of law is independent migration of ions
  • D. None of the above

Explanation: The law is valid for weak and strong electrolytes both.

Correct answer: The law is valid for weak electrolytes only
  • A. Zn(s)
  • B. Cr(s)
  • C. H2(g)
  • D. Fe 2+(aq)

Explanation: Zn2+(aq) is having minimum reduction potential. So oxidation potential of Zn(s) will be maximum and it will be strongest reducing agent.

Correct answer: Zn(s)
  • A. 0.2 mole of 2 Cu+ will go into solution
  • B. 560 ml O2 liberate
  • C. No loss in weight
  • D. 2 gram of copper goes into solution as Cu2+

Explanation: During electrolysis of CuSO4 solution using Cu electrodes, the cell reaction is: Anode: Cu (s) → Cu++ + 2e- Cathode: Cu++(aq) + 2e- →…

Correct answer: 2 gram of copper goes into solution as Cu2+
  • A. H2
  • B. CI2
  • C. O2
  • D. Na

Explanation: For aqueous solution of NaCl at cathode.H2O is reduced to H2 as its Ered is higher than Na+. 2H2O + 2e- → H2 + 2OH-

Correct answer: H2
  • A. Electromotive force
  • B. Electrode potential
  • C. Cell potential
  • D. Both A and C

Explanation: Emf or cell potential is the force used to drive electron in a circuit.

Correct answer: Both A and C
  • A. N
  • B. F
  • C. O
  • D. CI

Explanation: Fluorine is very strong oxidizing agent and is at the bottom of ECS. Indicating its highest Eered= +2.87V.

Correct answer: F
  • A. H2
  • B. CI2
  • C. O2
  • D. Na

Explanation: During electrolysis of brine, chlorine is obtained on anode.

Correct answer: CI2
  • A. It is apparent charge on an atom in a compound
  • B. Its value is either zero, positive or negative
  • C. It can be variable
  • D. Xenon (Xe) can show maximum oxidation state +6 in its compounds

Explanation: Oxidation state or oxidation number, is the hypothetical charge of an atom if all of its bonds to other atoms were fully ionic.

Correct answer: Xenon (Xe) can show maximum oxidation state +6 in its compounds
  • A. They may be get deposited/released on the electrode surface
  • B. They may go out in the form of gases
  • C. Electrolytic material may get dissolved into the solution as ions
  • D. In Nelson cell, Na metal is a primary product

Explanation: The correct answer is D) In Nelson cell, Na metal is a primary product.

Correct answer: In Nelson cell, Na metal is a primary product