All Free Chemistry MCQs with Answers

Every Chemistry question in the bank, across all chapters, each with the correct answer and a written explanation. Free and unlimited, with no account needed.

13,720 questions · page 558 of 686

  • A. 17
  • B. 3
  • C. 1
  • D. 8

Explanation: Chlorine atom has 7 electrons in it's valence shell, however the question is asking about chloride ion which has 1 extra electron.

Correct answer: 8
  • A. Cl2
  • B. CH4
  • C. HF
  • D. HI

Explanation: Each sp3 hybrid orbital of carbon overlaps 1s-orbital of hydrogen to form C-H sigma bonds.

Correct answer: CH4
  • A. Greater
  • B. Zero
  • C. Lesser
  • D. Variable

Explanation: Down the group ionization energy decreases due to increase in number of shell, shielding effect and atomic size.

Correct answer: Lesser
  • A. Increases from left to right in a period
  • B. Increases from top to bottom in a group.
  • C. Does not change in a period
  • D. Does not change in a group

Explanation: Ionization energy is increases from left to right in a period.

Correct answer: Increases from left to right in a period
  • A. Pairing of electrons
  • B. Shifts of atoms
  • C. Sharing of atoms
  • D. None of the above

Explanation: The HF bond is formed by the sharing of the electrons, resulting in a strong bond that is highly polar.

Correct answer: Pairing of electrons
  • A. KO2, NO2
  • B. K2O2, KO3
  • C. K2O,NO2
  • D. NO2, N2O2

Explanation: In KO2, O2- → (superoxide) has one unpaired electron and NO2 also has one unpaired electron. Thus,KO2 and NO2 are paramagnetic.

Correct answer: KO2, NO2
  • A. Atomic/ionic radii
  • B. Shielding effect
  • C. Nature of orbital
  • D. All of the above

Explanation: 1.atomicsize 2.shielding effect 3.effective nuclear charge.

Correct answer: All of the above
  • A. High I. E of metal
  • B. Low lattice energy
  • C. Low E.A of non-metal
  • D. Low I.E of metal

Explanation: Metals of group IA and IIA have low ionization energy means high electropositive character and great tendency to form ionic bond.

Correct answer: Low I.E of metal
  • A. HI
  • B. HF
  • C. HCI
  • D. HBr

Explanation: %ionic character is directly related to electronegativity difference.

Correct answer: HF
  • A. The smaller size of Li+ imparts significant covalent character in LiF
  • B. The hydration energies of Li+ and F- are quite high
  • C. The lattice energy of LiF is quite high due to the smaller size of Li+ and F-
  • D. LiF has a strong polymeric network in solid form

Explanation: Due to the very small ionic radii of both Li⁺ and F⁻, the electrostatic attraction between them is extremely strong.

Correct answer: The lattice energy of LiF is quite high due to the smaller size of Li+ and F-
  • A. II > III > I > IV
  • B. II > III = I > IV
  • C. III > IV > I > II
  • D. IV > I > III > II

Explanation: Bond length is determined by bond order. The order from longest to shortest is single bond (II, III), partial double bond due to resonance…

Correct answer: II > III > I > IV
  • A. Nitrogen lacks available d-orbitals for bonding
  • B. The absence of NCl₅ is due to its instability
  • C. Nitrogen's smaller atomic size prevents NCl₅ formation
  • D. Nitrogen's inertness prevents NCl₅ formation

Explanation: Nitrogen is in the second period and has only s and p orbitals in its valence shell, limiting it to a maximum of four bonds.

Correct answer: Nitrogen lacks available d-orbitals for bonding
  • A. BeF₂
  • B. BCl₃
  • C. NH₃
  • D. ClF₃

Explanation: According to VSEPR theory, chlorine trifluoride (ClF₃) has a central chlorine atom with three bonding pairs and two lone pairs of…

Correct answer: ClF₃
  • A. The number of unpaired p-electrons
  • B. The number of paired d-electrons
  • C. The number of unpaired s-and p-electrons
  • D. The total number of s-and p-electrons in the outermost shell

Explanation: For elements in the second period, the maximum covalency is determined by the total number of valence orbitals available, which is one…

Correct answer: The total number of s-and p-electrons in the outermost shell
  • A. To decrease the number of electrons in the outermost shell
  • B. To attain an inert gas configuration
  • C. To increase the number of electrons in the outermost shell
  • D. To attain 18 electrons in the outermost shell

Explanation: Atoms form chemical bonds to achieve a more stable electron configuration, which is typically the configuration of the noble gases (like…

Correct answer: To attain an inert gas configuration
  • A. Ionization energy of A is high but electron affinity of B is low
  • B. The ionization energy of A is low but the electron affinity of B is high
  • C. Both ionization energy of A and electron affinity of B are high
  • D. Both ionization energy of A and electron affinity of B are low

Explanation: Ionic bond formation involves the transfer of electrons. This is most favorable when one atom (the metal) can lose an electron easily (low…

Correct answer: The ionization energy of A is low but the electron affinity of B is high
  • A. NaCl
  • B. CsF
  • C. KCl
  • D. HF

Explanation: Ionic character is greatest when the difference in electronegativity between the two atoms is largest.

Correct answer: CsF
  • A. Angular
  • B. Trigonal pyramidal
  • C. Tetrahedral
  • D. See-saw

Explanation: An AB₄ molecule has a central atom bonded to four surrounding atoms. Such species can adopt geometries like tetrahedral (AX₄), see-saw…

Correct answer: Angular
  • A. Br-Br > I-I
  • B. Cl-Cl < F-F
  • C. C≡ C < N≡ N
  • D. All are correct

Explanation: This statement is incorrect. While bond energy generally increases up a group, the F-F bond is anomalously weak due to strong repulsion…

Correct answer: Cl-Cl < F-F
  • A. I only
  • B. I and II only
  • C. I and III only
  • D. II only
  • E. I, II and III

Explanation: Bond energy is a critical concept in understanding chemical bonding and is defined through multiple perspectives:Option I: It is indeed…

Correct answer: I, II and III