All Free Chemistry MCQs with Answers
Every Chemistry question in the bank, across all chapters, each with the correct answer and a written explanation. Free and unlimited, with no account needed.
13,720 questions · page 558 of 686
- A. 17
- B. 3
- C. 1
- D. 8
Explanation: Chlorine atom has 7 electrons in it's valence shell, however the question is asking about chloride ion which has 1 extra electron.
Correct answer: 8- A. Cl2
- B. CH4
- C. HF
- D. HI
Explanation: Each sp3 hybrid orbital of carbon overlaps 1s-orbital of hydrogen to form C-H sigma bonds.
Correct answer: CH4- A. Greater
- B. Zero
- C. Lesser
- D. Variable
Explanation: Down the group ionization energy decreases due to increase in number of shell, shielding effect and atomic size.
Correct answer: Lesser11144. The ionization energy:
- A. Increases from left to right in a period
- B. Increases from top to bottom in a group.
- C. Does not change in a period
- D. Does not change in a group
Explanation: Ionization energy is increases from left to right in a period.
Correct answer: Increases from left to right in a period- A. Pairing of electrons
- B. Shifts of atoms
- C. Sharing of atoms
- D. None of the above
Explanation: The HF bond is formed by the sharing of the electrons, resulting in a strong bond that is highly polar.
Correct answer: Pairing of electrons- A. KO2, NO2
- B. K2O2, KO3
- C. K2O,NO2
- D. NO2, N2O2
Explanation: In KO2, O2- → (superoxide) has one unpaired electron and NO2 also has one unpaired electron. Thus,KO2 and NO2 are paramagnetic.
Correct answer: KO2, NO2- A. Atomic/ionic radii
- B. Shielding effect
- C. Nature of orbital
- D. All of the above
Explanation: 1.atomicsize 2.shielding effect 3.effective nuclear charge.
Correct answer: All of the above- A. High I. E of metal
- B. Low lattice energy
- C. Low E.A of non-metal
- D. Low I.E of metal
Explanation: Metals of group IA and IIA have low ionization energy means high electropositive character and great tendency to form ionic bond.
Correct answer: Low I.E of metal- A. HI
- B. HF
- C. HCI
- D. HBr
Explanation: %ionic character is directly related to electronegativity difference.
Correct answer: HF- A. The smaller size of Li+ imparts significant covalent character in LiF
- B. The hydration energies of Li+ and F- are quite high
- C. The lattice energy of LiF is quite high due to the smaller size of Li+ and F-
- D. LiF has a strong polymeric network in solid form
Explanation: Due to the very small ionic radii of both Li⁺ and F⁻, the electrostatic attraction between them is extremely strong.
Correct answer: The lattice energy of LiF is quite high due to the smaller size of Li+ and F-- A. II > III > I > IV
- B. II > III = I > IV
- C. III > IV > I > II
- D. IV > I > III > II
Explanation: Bond length is determined by bond order. The order from longest to shortest is single bond (II, III), partial double bond due to resonance…
Correct answer: II > III > I > IV- A. Nitrogen lacks available d-orbitals for bonding
- B. The absence of NCl₅ is due to its instability
- C. Nitrogen's smaller atomic size prevents NCl₅ formation
- D. Nitrogen's inertness prevents NCl₅ formation
Explanation: Nitrogen is in the second period and has only s and p orbitals in its valence shell, limiting it to a maximum of four bonds.
Correct answer: Nitrogen lacks available d-orbitals for bonding11153. Which molecule is T-shaped?
- A. BeF₂
- B. BCl₃
- C. NH₃
- D. ClF₃
Explanation: According to VSEPR theory, chlorine trifluoride (ClF₃) has a central chlorine atom with three bonding pairs and two lone pairs of…
Correct answer: ClF₃- A. The number of unpaired p-electrons
- B. The number of paired d-electrons
- C. The number of unpaired s-and p-electrons
- D. The total number of s-and p-electrons in the outermost shell
Explanation: For elements in the second period, the maximum covalency is determined by the total number of valence orbitals available, which is one…
Correct answer: The total number of s-and p-electrons in the outermost shell- A. To decrease the number of electrons in the outermost shell
- B. To attain an inert gas configuration
- C. To increase the number of electrons in the outermost shell
- D. To attain 18 electrons in the outermost shell
Explanation: Atoms form chemical bonds to achieve a more stable electron configuration, which is typically the configuration of the noble gases (like…
Correct answer: To attain an inert gas configuration- A. Ionization energy of A is high but electron affinity of B is low
- B. The ionization energy of A is low but the electron affinity of B is high
- C. Both ionization energy of A and electron affinity of B are high
- D. Both ionization energy of A and electron affinity of B are low
Explanation: Ionic bond formation involves the transfer of electrons. This is most favorable when one atom (the metal) can lose an electron easily (low…
Correct answer: The ionization energy of A is low but the electron affinity of B is high- A. NaCl
- B. CsF
- C. KCl
- D. HF
Explanation: Ionic character is greatest when the difference in electronegativity between the two atoms is largest.
Correct answer: CsF- A. Angular
- B. Trigonal pyramidal
- C. Tetrahedral
- D. See-saw
Explanation: An AB₄ molecule has a central atom bonded to four surrounding atoms. Such species can adopt geometries like tetrahedral (AX₄), see-saw…
Correct answer: Angular- A. Br-Br > I-I
- B. Cl-Cl < F-F
- C. C≡ C < N≡ N
- D. All are correct
Explanation: This statement is incorrect. While bond energy generally increases up a group, the F-F bond is anomalously weak due to strong repulsion…
Correct answer: Cl-Cl < F-F- A. I only
- B. I and II only
- C. I and III only
- D. II only
- E. I, II and III
Explanation: Bond energy is a critical concept in understanding chemical bonding and is defined through multiple perspectives:Option I: It is indeed…
Correct answer: I, II and III