Free Aldehydes and Ketones MCQs with Answers
679 Aldehydes and Ketones MCQs from Chemistry, each with the correct answer and a written explanation of why it is correct. Free and unlimited, with no account needed.
Aldehydes and ketones contain the polar carbonyl group, but aldehydes are generally more readily oxidised and more reactive than ketones. Coverage includes preparation by oxidation or reduction routes, nucleophilic addition of reagents such as hydrogen cyanide and bisulfite, and tests that distinguish aldehydes from ketones.
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679 questions · page 15 of 34
- A. They have higher boiling points than that of alkalies
- B. They have lower boiling points than that of alcohols
- C. Aldehydes are present in essential oils and ketonic group is presentin camphor
- D. Aldehydes have H-bonding but ketones do not have
Explanation: Statement of option d is incorrect. Aldehydes and ketones both can show H-bonding.
Correct answer: Aldehydes have H-bonding but ketones do not have- A. Glucose and fructose
- B. Glucose and maltose
- C. Propanone and benzaldehyde
- D. Hydroxypropanone and benzaldehyde
Explanation: Option A is correct. Glucose and fructose are both reducing sugars, which can be distinguished by Fehling's solution.
Correct answer: Glucose and fructose- A. C2H5COCH3
- B. C2H5CH(CH3)OH
- C. CH3COCH3
- D. C2H5CH2CHO
Explanation: When HCN reacts with a ketone, two new bonds form. The H from HCN adds to 0 in C=O to form C-OH bond and -CN adds to C to form C- CN bond.
Correct answer: C2H5COCH3- A. Carbonyl carbon contains no lone pair
- B. Carbonyl oxygen contains two lone pair
- C. Carbonyl group contains two lone pairs
- D. All of these
Explanation: A) Carbonyl carbon contains no lone pair: A carbonyl group consists of a carbon atom double-bonded to an oxygen atom (C=O).
Correct answer: All of these- A. Solidification.
- B. Chromatography.
- C. Re-distillation.
- D. Steam distillation.
Explanation: The answer is: Re-distillation. During the oxidation of ethanol to get an acetaldehyde, acetaldehyde is immediately distilled off to avoid…
Correct answer: Re-distillation.- A. The addition product formed with propene would not be stable
- B. Propanone is more susceptible to nucleophilic attack than propene
- C. Propanone is more susceptible to electrophilic attack than propene
- D. Propanone is more susceptible to free radical attack than propene
Explanation: Option B is correct.Propanone is more susceptible to nucleophilic attack than propene.
Correct answer: Propanone is more susceptible to nucleophilic attack than propene- A. Methanol
- B. Methanoic acid
- C. Acetone
- D. Acet Aldehyde
Explanation: Aldehydes on oxidation give carboxylic acids. As methanoic acid is carboxylic acid, so, option B is correct.
Correct answer: Methanoic acid- A. Calcium acetate
- B. Calcium formate
- C. Ethyl acetate
- D. Acetic Acid
Explanation: Acetone is prepared by dry distillation of calcium acetate.Hence, option A is correct.
Correct answer: Calcium acetate- A. Formic acid
- B. Ethanoic acid
- C. Propanoic Acid
- D. Butyric Acid
Explanation: Ketones on oxidation give carboxylic acids with 1 carbon atom less than ketone.
Correct answer: Ethanoic acid- A. o-nitro toluene
- B. p-nitro toluene
- C. m-nitro toluene
- D. Benzoic acid
Explanation: When toluene is subjected to oxidation, only the methyl group undergoes oxidation while the benzene ring remains intact.
Correct answer: Benzoic acid- A. Acetylene
- B. Phenol
- C. Toluene
- D. Benzene
Explanation: Beneze is oxidized in presence of vanadium peroxide (V2O5) producing maleic anhydride.STB Pg- 157Hence, option D is correct.
Correct answer: Benzene- A. Nucleophile and electrophile
- B. Base and nucleophile
- C. Electrophile and nucleophile
- D. Nucleophile and base
Explanation: In the Aldol condensation, NaOH acts as a base by accepting a proton, and in the Cannizaro's reaction, it acts as a nucleophile by…
Correct answer: Base and nucleophile- A. K2Cr2O7
- B. H2SO4
- C. KMnO4
- D. HCI
Explanation: Aldehydes are not easily oxidized by hydrochloric acid (HCl), as it's not a effective oxidizing agent for aldehydes.
Correct answer: HCI- A. 2.4 - DNPH test
- B. Tollen's Test
- C. Sodium Nitro Prusside Test
- D. Fehling's Solution
Explanation: Aldehydes typically do not react with sodium nitroprusside, which is a test for the detection of ketones.
Correct answer: Sodium Nitro Prusside Test- A. 1,3-Diisopropylpropan-2-on
- B. 2,4-Dimethylpentan-3-one
- C. 2,4-Dimethylpentan-2-one
- D. 1,3-Dimethylpropan-2-one
Explanation: 2,4-Dimethylpentan-3-oneExplanation:Diisopropyl ketone refers to a ketone with two isopropyl groups attached to the carbonyl carbon.The…
Correct answer: 2,4-Dimethylpentan-3-one296. The appearance of a silver mirror in Toliens test indicates the presence of which of the following?
- A. A ketone
- B. An aldehyde
- C. An acid
- D. An alcohol
Explanation: Aldehyde (Correct)Explanation: Aldehydes reduce Tollens' reagent (Ag⁺) to metallic silver, creating a silver mirror on the test tube.
Correct answer: An aldehyde297. The reduction of aldehyde and ketone is to alkanes in the presence of Zinc amalgam and HCl is called
- A. Clemmensen reduction
- B. Williamson's synthesis
- C. Wolf-Kishner reduction
- D. Dow process
Explanation: Clemmensen reduction is a chemical reaction described as a reduction of ketones or aldehydes to alkanes using zinc amalgam and…
Correct answer: Clemmensen reduction- A. Hydrazine
- B. Hydrazone
- C. Oxime
- D. Imine
Explanation: When aldehydes and ketones react with hydroxylamine (NH₂OH), they form a class of compounds known as oximes.
Correct answer: Oxime- A. Reduction of aldehydes
- B. Oxidation of Copper(II)
- C. Oxidation of aldehyde
- D. Oxidation of Ketone
Explanation: Fehling's solution is specifically designed to test for aldehydes, which are oxidized to carboxylic acids during the reaction.
Correct answer: Oxidation of aldehyde- A. Nucleophilic Addition Reactions
- B. Reduction to Alcohols
- C. Formation of Hydrazones
- D. Reaction with Fehling's Solution
Explanation: Fehling's solution is used to test for the presence of reducing sugars and aldehydes.
Correct answer: Reaction with Fehling's Solution