Which of the following statements about the reaction given below are correct? IO3-(aq) + 2I-(aq) + 6H+(aq) + 6Cl-(aq) -> 3ICl2-(aq) + 3H2O(l)
Correct answer: A. The oxidation number of iodine in the iodate ion, IO3-(aq), changes from +5 to +1.
- A. The oxidation number of iodine in the iodate ion, IO3-(aq), changes from +5 to +1.
- B. The oxidation number of iodine in the iodide ion I-, changes from -1 to +2
- C. The oxidation number of chlorine in the iodide ion I- , changes from -1 to -2
- D. Iodate ions are oxidized
Explanation
In IO3-, iodine has an oxidation number of +5 which we can calculate from the oxidation number of oxygen which is -2, and the collective oxidative number of the iodate ion which is -1. On the other hand, we have ICl2- ion in which iodine has the oxidative number of +1 which we can find from the same method but in this case, we have chlorine having the oxidation state of -1. This reduction in the oxidation state of iodide from +5 to +1 is true thus the answer is A.
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