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Which of the following statements about the reaction given below are correct? IO3-(aq) + 2I-(aq) + 6H+(aq) + 6Cl-(aq) -> 3ICl2-(aq) + 3H2O(l)

Correct answer: A. The oxidation number of iodine in the iodate ion, IO3-(aq), changes from +5 to +1.

  • A. The oxidation number of iodine in the iodate ion, IO3-(aq), changes from +5 to +1.
  • B. The oxidation number of iodine in the iodide ion I-, changes from -1 to +2
  • C. The oxidation number of chlorine in the iodide ion I- , changes from -1 to -2
  • D. Iodate ions are oxidized

Explanation

In IO3-, iodine has an oxidation number of +5 which we can calculate from the oxidation number of oxygen which is -2, and the collective oxidative number of the iodate ion which is -1. On the other hand, we have ICl2- ion in which iodine has the oxidative number of +1 which we can find from the same method but in this case, we have chlorine having the oxidation state of -1. This reduction in the oxidation state of iodide from +5 to +1 is true thus the answer is A.

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