Which of the following atoms in the given oxidation state have the highest electro negativity.
Correct answer: A. Mo(ii)
- A. Mo(ii)
- B. Mo(iii)
- C. Mo(v)
- D. Mo(vi)
Explanation
Students should learn the Mo(ii) has the lowest oxidation state and highest electronegativity.Compared to the other given oxidation states of Molybdenum, Mo(ii) has the highest electronegativity because the valence electrons are closer to the nucleus and experience a greater effective nuclear charge. This makes Mo(ii) more electronegative than Mo(iii), Mo(v), and Mo(vi), which have more valence electrons and a higher effective nuclear charge that is more distributed across the electron cloud. Molybdenum in the +2 oxidation state has the electronic configuration: [Kr] 4d5. The oxidation state with a completely filled 4d subshell (Mo(ii)) has relatively lower electronegativity than other oxidation states. When comparing the electronegativity of the same element in different oxidation states, the electronegativity generally decreases as the oxidation state increases.Therefore, among the given oxidation states, Mo(ii) would have the highest electronegativity.Students should learn the Mo(ii) has the lowest oxidation state and highest electronegativity
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About Periodic Properties and Trends
Periodic properties arise from electron configuration and effective nuclear charge, producing trends in atomic and ionic radius, ionization energy, electron affinity, electronegativity, metallic character and reactivity. Comparisons run across periods and down groups, with attention to common exceptions. The topic also relates these trends to the behavior of s-block and p-block elements.
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