Which of the following aqueous solutions would have the highest boiling point?
Correct answer: C. 0.15 m CaCl2
- A. 0.20 m glucose
- B. 0.20 m NaCl
- C. 0.15 m CaCl2
- D. 0.25 m sucrose
Explanation
Boiling-point elevation depends on the total number of dissolved particles, approximately i x molality: glucose gives 0.20, NaCl gives 2 x 0.20 = 0.40, CaCl2 gives 3 x 0.15 = 0.45, and sucrose gives 0.25. Thus 0.15 m CaCl2 has the greatest particle concentration and highest boiling point; students may choose 0.20 m NaCl by overlooking the three ions produced by CaCl2.
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