When different alkenes are treated with hot concentrated KMnO4 solution, different products are obtained. Which of the following alkenes produces two moles of carboxylic acids?
Correct answer: B. R - CH = CH - R
- A. H2C = CH2
- B. R - CH = CH - R
- C. R1R2C = CR3R4
- D. R1R2C = CH3R4
Explanation
When R - CH - CH - R alkene is treated with hot concentrated KMnO4 solution, it undergoes oxidative cleavage to produce two moles of carboxylic acids. The carbon-carbon double bond in the alkene is broken, resulting in the formation of two carboxylic acid groups.The other options do not have the required structure to yield carboxylic acids when treated with hot concentrated KMnO4 solution.
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About Chemistry of Hydrocarbons
Hydrocarbons are studied through the structures and reactions of alkanes, alkenes, alkynes and aromatic compounds. Coverage includes free radical substitution in alkanes, electrophilic addition to carbon-carbon multiple bonds, benzene substitution, aromatic stability and the difference between addition reactions of alkenes and substitution reactions of benzene.
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