Asked in Premeth Test 11 — S and P Block, D Block and Chemical Bonding (13 March 2025) 2025Moderate

When a metal carbonate is heated at 100°C, which of the following compounds will readily decompose?

Correct answer: C. BeCO₃

  • A. BaCO₃
  • B. MgCO₃
  • C. BeCO₃
  • D. SrCO₃

Explanation

The thermal stability of metal carbonates increases down a group in the periodic table because the larger cations (lower down the group) have a lower charge density. This reduces their polarizing effect on the carbonate ion, making the carbonate more stable and less likely to decompose.Key Points:BeCO₃ (Beryllium Carbonate):Beryllium is the smallest and most polarizing cation in Group 2.It strongly distorts the carbonate ion, making it unstable and prone to decomposition even at relatively low temperatures.MgCO₃ (Magnesium Carbonate):Magnesium has a slightly larger ionic radius than beryllium, making MgCO₃ more stable than BeCO₃ but less stable than heavier carbonates.BaCO₃ (Barium Carbonate) and SrCO₃ (Strontium Carbonate):Barium and strontium are larger cations, making their carbonates the most stable in the group. They decompose only at very high temperatures.Thermal Stability Trend:BeCO₃<MgCO₃<SrCO₃<BaCO₃Conclusion:BeCO₃ readily decomposes when heated at 100°C due to its low thermal stability

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About Reactions of Group II Elements

Group II reactions cover the behaviour of beryllium, magnesium, calcium, strontium and barium with water, oxygen, halogens, acids and nitrogen. The trends in reactivity, hydroxide solubility and basicity, along with the thermal decomposition of carbonates and nitrates, depend on increasing atomic size down the group.

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