What should be the length of a simple pendulum whose period is 6.28 seconds at a place where g = 10 ms-2?
Correct answer: D. 10 m
- A. 0.28 m
- B. 10.8 m
- C. 6.28 m
- D. 10 m
Explanation
10 m: This option represents the correct length for the simple pendulum. The period of a simple pendulum is given by the formula T = 2π√(L/g), where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity. Rearranging the formula, we have L = (T^2 * g) / (4π^2), where T = 6.28 s and g = 10 ms^-2. Plugging in these values, we get L = (6.28^2 * 10) / (4π^2) ≈ 9.99 m, which can be approximated as 10 m.
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About Simple Harmonic Motion
Simple harmonic motion is oscillation in which acceleration is directly proportional to displacement and directed toward the equilibrium position. Work includes displacement, velocity, acceleration, phase, period, frequency, amplitude and energy, with applications to springs and simple pendulums. The restoring force and the conditions for SHM distinguish it from general periodic motion.
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