Asimple pendulum has mass M, length L and time period T. What is the period of oscillation of the pendulum with mass 4M and length 0.49L?
Correct answer: A. 0.7T
- A. 0.7T
- B. T
- C. 2T
- D. 3T
Explanation
Option A is correct since the formula for a time period of a simple pendulum is T=2pi * root of l/g. Therefore substituting the values: 2*pi* the root of L/9.81 is T. If 0.49 is placed with l, the time-period becomes 0.7T. Option B is incorrect since it states that the period remains the same, which cannot happen since length changes Option C is incorrect since time-period will double if the length becomes 4 times which is not the case Option D is incorrect since time-period will triple if the length becomes 9 times which is not the case
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About Simple Harmonic Motion
Simple harmonic motion is oscillation in which acceleration is directly proportional to displacement and directed toward the equilibrium position. Work includes displacement, velocity, acceleration, phase, period, frequency, amplitude and energy, with applications to springs and simple pendulums. The restoring force and the conditions for SHM distinguish it from general periodic motion.
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