What mass of NaOH is present in 0.5 mol of sodium hydroxide?
Correct answer: D. 20 g
- A. 40 g
- B. 2.5 g
- C. 5 g
- D. 20 g
Explanation
Sodium hydroxide = NaOH Molar mass of NaOH = 39.99 We know that number of moles = mass/molar mass 0.5 = mass/39.99 Mass =19.99 19.99 g can be written as 20 g.
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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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