Moderate

The mass of 𝑁𝑎𝑂𝐻 needed to prepare 0.2 molal solution in 500𝑔 pure water at 4℃ is:

Correct answer: B. 4.0𝑔

A. 0.4𝑔
B. 4.0𝑔
C. 1.5𝑔
D. 1.0𝑔

Explanation

As for 0.2 molal solution 0.2 mole of NaOH is needed to dissolve in 1000 grams of water. For 500 grams0.2÷1000×500=0.1 mole of NaOHThe mass for 0.1 mole of NaOH is 40 g/mol×0.1mol = 4 grams.

Last updated 1 September 2026

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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.

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The mass of 𝑁𝑎𝑂𝐻 needed to prepare 0.2 molal solution in 500𝑔 pure water at 4℃ is:

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