The mass of ππππ» needed to prepare 0.2 molal solution in 500π pure water at 4β is:
Correct answer: B. 4.0π
- A. 0.4π
- B. 4.0π
- C. 1.5π
- D. 1.0π
Explanation
As for 0.2 molal solution 0.2 mole of NaOH is needed to dissolve in 1000 grams of water. For 500 grams0.2Γ·1000Γ500=0.1 mole of NaOHThe mass for 0.1 mole of NaOH is 40 g/molΓ0.1mol = 4 grams.
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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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