What mass of CaCO3 gives 48.8 litres (measured at STP) of CO2, on strong heating?_.

Explanation

Write the balanced chemical equation: CaCO3(s) -> CaO(s) + CO2(g)Calculate the moles of CO2:At STP, 1 mole of any gas occupies 22.4 liters.So, moles of CO2 = 48.8 L / 22.4 L/mol = 2.18 molesUse the mole ratio from the balanced equation:1 mole of CaCO3 produces 1 mole of CO2. So, moles of CaCO3 = 2.18 molesCalculate the mass of CaCO3:Molar mass of CaCO3 = 40.08 g/mol + 12.01 g/mol + (3 * 16.00 g/mol) = 100.09 g/mol Mass of CaCO3 = moles * molar mass = 2.18 moles * 100.09 g/mol = 218.2 gTherefore, the mass of CaCO3 that gives 48.8 liters of CO2 at STP is approximately 218.2 grams.