9.03 x 10²³ molecules of an ideal gas at STP will have volume of:
Correct answer: C. 33.6 dm³
- A. 11.2 dm³
- B. 22.4 dm³
- C. 33.6 dm³
- D. 44.8dm³
Explanation
9.03 x 10 to the 23 molecules divided by 6.02 x 10 to the 23 is 1.5 moles, and at STP each mole occupies 22.4 dm3, so the volume is 1.5 times 22.4, which is 33.6 dm3. 22.4 dm3 is the volume of one mole, not of this amount.
This question appeared on the UHS MDCAT 2026 paper, which you can sit online with every answer explained.
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About Moles and Avogadro's Number
The mole connects the microscopic number of particles with measurable mass, using Avogadro's number, 6.022 × 10²³ particles per mole. Questions involve molar mass, conversion between mass, moles and particles, percentage composition, empirical and molecular formulas, and distinguishing atoms, molecules, ions and formula units.
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