What is the value of maximum COP in case of absorption refrigeration, if refrigeration provided is at temperature, TR (where, T1 and T2 are source & surrounding temperatures respectively.) ?
Correct answer: A. TR/(T2 - TR) × (T1 - T2)/T1
- A. TR/(T2 - TR) × (T1 - T2)/T1
- B. TR/(T2 - TR) × T1/(T1 - T2)
- C. TR/(T1 - TR) × (T1 - T2)/T1
- D. None of these
Explanation
The ideal absorption refrigerator combines the refrigerator factor TR/(T2 - TR) with the heat-engine factor (T1 - T2)/T1. Their product gives the maximum COP shown in option a.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? support@testustad.com
Practise Chemical Engineering Thermodynamics
598 free Chemical Engineering Thermodynamics MCQs from Chemical Engineering, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Exams that ask Chemical Engineering questions like this
Chemical Engineering is on this paper prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for it.
More Chemical Engineering Thermodynamics questions
Throttling (Joule-Thomson effect) process is a constant _____________ process?
The equation Tds = dE - PdV applies to___________________?
Heat pump_______________________?
Number of degrees of freedom for a three phase system in equilibrium comprising of three non-reacting chemical species is__________________?
Gibbs-Duhem equation_____________________?
Entropy change of mixing two liquid substances depends upon the_________________?