What is the value of capacitance that must be connected in parallel with 50 pF condenser to make an equivalent capacitance of 150 pF ?
Correct answer: B. 100 pF
- A. 50 pF
- B. 100 pF
- C. 150 pF
- D. 200 pF
Explanation
Capacitances in parallel add directly, so the required capacitor is 150 − 50 = 100 pF. Series capacitances would not be added directly, which is the common trap here.
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