The electrostatic force between two charges of one coulomb each and placed at a distance of 0.5 m will be____________?
Correct answer: D. 36 x 10^9 N
- A. 36 x 10fa
- B. 36 x 10^7 N
- C. 36 x 10^8 N
- D. 36 x 10^9 N
Explanation
Using Coulomb’s law, F = kq₁q₂/r² = 9 × 10⁹ × 1 × 1/(0.5)² = 36 × 10⁹ N. Thus the force is 36 × 10⁹ newtons.
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