What is the speed of 2.0 kg metallic bob at the mean position of a simple pendulum, when released from its extreme position 0.5m high? (g = 10 ms-2)
Correct answer: A. 3.16 ms-1
- A. 3.16 ms-1
- B. 10 ms-1
- C. 100 ms-1
- D. 50 ms -1
Explanation
At the extreme displacement, the potential energy, (PE= mgh = 2x10x0.5= 10J) is equal to the total energy of the system.At the mean position, we have all the potential energy being converted to kinetic energy= KE =10 J = ½ mv210J = 1/2mv2mv2=20 -> 2v2 =20 -> v2= 10, hence v =3.16 ms-1
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About Simple Harmonic Motion
Simple harmonic motion is oscillation in which acceleration is directly proportional to displacement and directed toward the equilibrium position. Work includes displacement, velocity, acceleration, phase, period, frequency, amplitude and energy, with applications to springs and simple pendulums. The restoring force and the conditions for SHM distinguish it from general periodic motion.
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