Asked in PMC Practice Test 32 (2021) 2021Moderate

If the maximum velocity of SHM is ao, the period of oscillation is _.

Correct answer: A. 2πxo/ao

  • A. 2πxo/ao
  • B. 2πao/xo
  • C. 2πaoxo
  • D. 2π/aoxo

Explanation

In simple harmonic motion, the velocity is given byV max = wxoWhere,w= 2π/TVmax = aO Therefore the equation becomesaO = {2π/T} x (xo)The time period of oscillation is represented by TSo the equation becomes,T= 2πxo / aO Mathematically options B, C & D are incorrect

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About Simple Harmonic Motion

Simple harmonic motion is oscillation in which acceleration is directly proportional to displacement and directed toward the equilibrium position. Work includes displacement, velocity, acceleration, phase, period, frequency, amplitude and energy, with applications to springs and simple pendulums. The restoring force and the conditions for SHM distinguish it from general periodic motion.

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