What is the reason for the steady current flow in a circuit?
Correct answer: B. Presence of a constant voltage source in circuit
- A. Presence of very large resistance
- B. Presence of a constant voltage source in circuit
- C. presence of switch in circuit
- D. Presence of ammeter in circuit
Explanation
A steady current flows because a constant voltage source, such as a battery, keeps a constant potential difference across the circuit. A switch only completes the circuit and an ammeter only measures the current, while a very large resistance would reduce it.
This question appeared on the UHS MDCAT 2026 paper, which you can sit online with every answer explained.
Report an error
The more specific you are, the faster it gets fixed. A source beats an opinion.
Prefer email? [email protected]
About Steady Current
Steady current is the continuous flow of charge at a constant rate through a conductor. The topic covers current, charge, potential difference, resistance, Ohm's law, resistivity and electrical power, along with series and parallel circuits, while distinguishing conventional current direction from electron motion.
Practise Current Electricity
1,053 free Current Electricity MCQs from Physics, each with the correct answer and an explanation. Unlimited attempts, no account needed.
Discussion
Stuck on an option, or know a faster way to get there? Ask or explain it here.
No comments yet. Be the first to explain this one.
Exams that ask Physics questions like this
Physics is on 16 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.
More Steady Current questions
A certain X-ray tube requires a current of 5mA at a voltage of 60kv. The rate of energy dissipation (in watts) is:
Kirchofrs current law (KM.) Is based upon law Of conservation of:
A total charge of 100C flows through a 12W bulb in a time of 50 second. What is the potential difference across the bulb during this time?
A 0.01A moving coil Galvanometer of 5 Ω resistance can be converted into a 0.2A ammeter by a resistance R with the Galvanometer when r is: