A 0.01A moving coil Galvanometer of 5 Ω resistance can be converted into a 0.2A ammeter by a resistance R with the Galvanometer when r is:
Correct answer: A. 0.25 Ω in parallel
- A. 0.25 Ω in parallel
- B. 0.25 Ω in series
- C. 0.50 Ω in parallel
- D. 0.50 Ω in series
Explanation
A galvanometer is converted into an ammeter by connecting a low resistance in parallel with the galvanometer. This low resistance is called shunt resistance. The formula for calculating shunt resistance isIR = ir0.01 x 5 = 0.2rr = 0.25A
This question appeared on the ETEA MDCAT 2015 paper, which you can sit online with every answer explained.
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