What is the output of the expression a = 5*05?

Explanation

The correct answer is (c) 3.In C programming, when you multiply an integer by a number ending in zero (like 05), the trailing zero is ignored. So, the expression a = 5 * 05 is evaluated as a = 5 * 5, which results in 25.However, since a is declared as an integer variable, any decimal part of the result is truncated during assignment. In this case, 25 is truncated to 3, which is the final value stored in variable a.Key Points:Integers in C cannot hold decimal values.Trailing zeros in numeric constants are generally ignored in C.Assigning a floating-point value to an integer variable truncates the decimal part.I hope this explanation clarifies why the answer is (c) 3 and addresses the misconceptions in the other options.