What is the mass percent of silver in silver notrate, AgNO3?
Correct answer: C. 63.5%
- A. 64.5%
- B. 65.6%
- C. 63.5%
- D. 61.5%
Explanation
The molar mass of AgNO3 is 107.9 g/mol + 14.0 g/mol + 3(16.0 g/mol) = 169.9 g/mol. Therefore, percentage of silver = (107.9 g/mol ÷ 169.9 g/mol) x 100 = 63.5%, so option c is correct. Students may choose b by using an incorrect molar mass for nitrate or by confusing silver's atomic percentage with its mass percentage.
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The mole connects the microscopic number of particles with measurable mass, using Avogadro's number, 6.022 × 10²³ particles per mole. Questions involve molar mass, conversion between mass, moles and particles, percentage composition, empirical and molecular formulas, and distinguishing atoms, molecules, ions and formula units.
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