58.5g of of NaCl per 1 dm3 of solution of NaCl in water the concentration of solution will be___________________?
Correct answer: C. 1 M
- A. 0.1 M
- B. 1 m
- C. 1 M
- D. 0.1 N
Explanation
The molar mass of NaCl is 58.5 g mol−1, so 58.5 g represents 1 mol. Since this amount is present in 1 dm3 of solution, molarity = 1 mol / 1 dm3 = 1 mol dm−3 = 1 M. Students may choose 0.1 M by misplacing the decimal or confusing dm3 with 10 dm3.
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About Moles and Avogadro's Number
The mole connects the microscopic number of particles with measurable mass, using Avogadro's number, 6.022 × 10²³ particles per mole. Questions involve molar mass, conversion between mass, moles and particles, percentage composition, empirical and molecular formulas, and distinguishing atoms, molecules, ions and formula units.
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