What is the empirical formula of a compound composed of O and Mn in equal weight ratio? [Mn = 55]
Correct answer: D. Mn2O7
- A. MnO
- B. MnO2
- C. Mn2O3
- D. Mn2O7
Explanation
The numerical solution is given below:Mn2O7 Mass of Mn = 55 x 2 = 110Mass of O= 16 x 7 = 112
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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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