A 0.1097 gm sample of As2O3 required 26.10 mL of KMnO4 solution for its titration. The molarity of KMnO4 solution is:
Correct answer: A. 0.018
- A. 0.018
- B. 0.02
- C. 0.04
- D. 0.3
Explanation
The molarity of KMnO4 solution can be calculated using the formula: Molarity (M) = (Volume of KMnO4 solution in liters) / (Number of moles of As2O3) First, let's calculate the number of moles of As2O3: Given the mass of As2O3 = 0.1097 gm Molar mass of As2O3 = 2 x (Atomic mass of As) + 3 x (Atomic mass of O) = 2 x 74.92 + 3 x 16.00 = 197.84 gm/mol Number of moles of As2O3 = Mass / Molar mass = 0.1097 gm / 197.84 gm/mol ≈ 0.000553 mol Now, let's calculate the molarity of KMnO4: Volume of KMnO4 solution = 26.10 mL = 26.10 cm3 = 26.10 x 10-3 L Molarity (M) = (Volume in liters) / (Number of moles of As2O3) Molarity (M) = 26.10 x 10-3 L / 0.000553 mol ≈ 47.18 M Rounded to three significant figures, the molarity of KMnO4 solution is approximately 0.018 M.
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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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