Asked in MDCAT Test Series — Electrostatics, Work and Energy

What is the change in kinetic energy of a proton when it is accelerated through a potential difference of 2MV?

Correct answer: C. 0.32 pJ

  • A. 0.32 μJ
  • B. 0.32 nJ
  • C. 0.32 pJ
  • D. 0.32 fJ

Explanation

Change in Kinetic energy is equivalent to work done.We know that W = VqWhere W is the work done, V is the potential difference through which the charged particle is accelerated, and q is the magnitude of charge.W = 2x106 (1.6x10-19) = 3.2x10-13J = 0.32 pJ

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About Electric Potential

Electric potential is the work done per unit positive charge in bringing it from infinity to a point, while potential difference compares energy change between two points. Work includes potential due to point charges, superposition of scalar potentials, equipotential surfaces, and the relation between electric field and potential.

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