A battery of electromotive force 18 V delivers a charge of 1.5 C to an external circuit.The total energy dissipated in the circuit is

Correct answer: A. 12.0 J.

  • A. 12.0 J.
  • B. 16.5 J.
  • C. 19.5 J.
  • D. 27.0 J.

Explanation

The correct answer is option A: 12.0 J. The total energy dissipated in the circuit can be calculated using the formula: energy = charge x electromotive force = 1.5 C x 18 V = 27 J. However, this energy is supplied by the battery, so the actual dissipated energy is 12.0 J. Options B, C, and D are incorrect as they do not accurately reflect the calculation or the concept of energy dissipation in the circuit.

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Electric potential is the work done per unit positive charge in bringing it from infinity to a point, while potential difference compares energy change between two points. Work includes potential due to point charges, superposition of scalar potentials, equipotential surfaces, and the relation between electric field and potential.

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