Asked in ETEA MDCAT 2014 2014Moderate

Using monochromatic light, interference fringes are produced on a screen placed a distance D from a pair of slits of separation a. The separation of the fringes is x. Both a and D are now doubled. What is the new fringe separation?

Correct answer: B. x

  • A. 2x
  • B. x
  • C. 3x
  • D. 4x

Explanation

For double slits: Wavelength λ = xa / Dwhere x: separation of fringes,a: slit separation / distance between slits,D = distance from slits to screen.So, separation of fringes, x = λD / aWhen both a and D are doubled, the fringe separation x = λD / aThe separation between the fringes denoted by x is directly proportional to distance between the slits and screen and inversely proportional to separation between the two slits. Thus doubling the two quantities would ultimately result in cancellation of each other.

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About Superposition and Interference

Superposition states that overlapping waves produce a resultant displacement equal to the algebraic sum of their individual displacements. Interference covers constructive and destructive interference, phase difference, path difference, coherent sources, and conditions for maxima and minima. It differs from diffraction, which involves spreading around openings or obstacles.

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