In Young's double slit experiment both the separation between the slits and the distance between the slits and the screen are halved; then the fringe width is:
Correct answer: B. Unchanged
- A. Halved
- B. Unchanged
- C. Doubled
- D. Zero
Explanation
In Young's double-slit experiment, the fringe width is calculated using the formula:wavelength * distance_to_screen / distance_between_slitsIf both the distance between the slits and the screen and the separation between slits are halved, they cancel each other's effect in the formula. Therefore, the fringe width remains unchanged.Option A (Halved) is incorrect because the changes cancel each other out. Option C (Doubled) is incorrect for the same reason. Option D (Zero) is incorrect because halving distances does not make the fringe width zero. Therefore, the correct answer is Option B: Unchanged.
This question appeared on the ETEA MDCAT 2016 paper, which you can sit online with every answer explained.
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Superposition states that overlapping waves produce a resultant displacement equal to the algebraic sum of their individual displacements. Interference covers constructive and destructive interference, phase difference, path difference, coherent sources, and conditions for maxima and minima. It differs from diffraction, which involves spreading around openings or obstacles.
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