Two copper conductors have equal length. The cross-sectional area of one conductor is four times that of the other. If the conductor having smaller cross-sectional area has a resistance of 40 ohms the resistance of other conductor will be_____________?
Correct answer: D. 10 ohms
- A. 160 ohms
- B. 80 ohms
- C. 20 ohms
- D. 10 ohms
Explanation
For equal material and length, resistance is inversely proportional to cross-sectional area. Increasing the area fourfold reduces 40 Ω to 40/4 = 10 Ω.
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