Three identical resistors are first connected in parallel and then in series. The resultant resistance of the first combination to the second will be_________________?
Correct answer: B. 1/9 times
- A. 9 times
- B. 1/9 times
- C. 1/3 times
- D. 3 times
Explanation
Three identical resistors of R in parallel give R/3, while in series they give 3R. The first result is therefore (R/3)/(3R) = 1/9 of the second.
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