Two blocks, X and Y, of masses m and 2m respectively are accelerated along a smooth horizontal surface by a force F applied to block X, as shown in the diagram. What is the magnitude of the force exerted by block Y on block X during this acceleration?
Correct answer: D. 2F/3
- A. 0
- B. F/3
- C. F/2
- D. 2F/3
- E. F
Explanation
Since , total mass = m+2m=3m Then when a= F/M (M=3m) so , a*= F/3m → (i) Now, we have to find the force on Y or F(y) = 2ma* Put the value of (i): F(y)= 2Fm/3m=2F/3= Answer Hence, all other options are incorrect.
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Displacement, velocity and acceleration describe motion, including the horizontal and vertical components of projectile motion. The chapter connects these quantities with Newton's laws, momentum and impulse, then applies conservation of momentum to collisions, distinguishing elastic collisions from inelastic ones.
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