Two blocks, X and Y, of masses m and 2m respectively are accelerated along a smooth horizontal surface by a force F applied to block X, as shown in the diagram. What is the magnitude of the force exerted by block Y on block X during this acceleration?
Correct answer: D. 2F/3
- A. 0
- B. F/3
- C. F/2
- D. 2F/3
- E. F
Explanation
Since , total mass = m+2m=3m Then when a= F/M (M=3m) so , a*= F/3m → (i) Now, we have to find the force on Y or F(y) = 2ma* Put the value of (i): F(y)= 2Fm/3m=2F/3= Answer Hence, all other options are incorrect.
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