A block with a mass of 0.1 kg is attached to a spring and placed on a horizontal frictionless table. The spring is stretched 20 cm when a force of 5 N is applied, the spring constant is:
Correct answer: B. 25 Nm-1
- A. 50 Nm-1
- B. 25 Nm-1
- C. 75 Nm-1
- D. 100 Nm-1
- E. 125 Nm-1
Explanation
The extension of the spring is 20cm which is 0.2mF=kx5=k(0.2)k=25Nm-1
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