Three reactions are giveni. H2SO4 + 2HF ⟶ F2 + SO2 + 2H2Oii. H2SO4 + 2HBr ⟶ Br2 + SO2 + 2H2Oiii. H2SO4 + 8HI ⟶ 4I2 + H2S + 4H2OThe strongest reducing agent in these reactions is:
Correct answer: A. HI
- A. HI
- B. HF
- C. HBr
- D. All of the above
Explanation
HI is the strongest reducing agent. The compounds having low dissociation energy are a stronger reducing agent than the others having high dissociation energy. The HI has low thermal stability as compared to HF, HCI, and HBr. HI can release H atoms easily as compared to HF, HCI, and HBr to reduce the other compound. The decreasing order of the reducing character is HI>HBr>HCl>HF
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About s-Block and p-Block Elements
The s and p blocks are studied through their valence-shell configurations, periodic trends and characteristic chemical properties. Work covers the reactions of Group I and Group II elements, the behaviour of Group IV elements, and how atomic size, ionization energy, electronegativity and metallic character change across periods and down groups.
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