Three reactions are giveni. H2SO4 + 2HF ⟶ F2 + SO2 + 2H2Oii. H2SO4 + 2HBr ⟶ Br2 + SO2 + 2H2Oiii. H2SO4 + 8HI ⟶ 4I2 + H2S + 4H2OThe strongest reducing agent in these reactions is:

Correct answer: A. HI

  • A. HI
  • B. HF
  • C. HBr
  • D. All of the above

Explanation

HI is the strongest reducing agent. The compounds having low dissociation energy are a stronger reducing agent than the others having high dissociation energy. The HI has low thermal stability as compared to HF, HCI, and HBr. HI can release H atoms easily as compared to HF, HCI, and HBr to reduce the other compound. The decreasing order of the reducing character is HI>HBr>HCl>HF

Written and checked by , M.Phil ChemistryLast updated
Report an error

The more specific you are, the faster it gets fixed. A source beats an opinion.

Prefer email? [email protected]

About s-Block and p-Block Elements

The s and p blocks are studied through their valence-shell configurations, periodic trends and characteristic chemical properties. Work covers the reactions of Group I and Group II elements, the behaviour of Group IV elements, and how atomic size, ionization energy, electronegativity and metallic character change across periods and down groups.

Practise s-Block and p-Block Elements

1,359 free s-Block and p-Block Elements MCQs from Chemistry, each with the correct answer and an explanation. Unlimited attempts, no account needed.

Discussion

Stuck on an option, or know a faster way to get there? Ask or explain it here.

No comments yet. Be the first to explain this one.

Exams that ask Chemistry questions like this

Chemistry is on 14 papers prepared for on TestUstad, and all of them draw the same bank, so this question is worth knowing for every one of them.

More s-Block and p-Block Elements questions