Three faradays of charge is passed through an aqueous solution of NaClO3 when NaClO4 is formed according to the reaction: NaClO3 + H2O → NaClO4 + H2How many moles of NaClO4 will be formed during the electrolysis?
Correct answer: C. 1.5
- A. 0.75
- B. 1.0
- C. 1.5
- D. 3.0
Explanation
In the given reaction: NaClO3 + H2O → NaClO4 + H2, the oxidation number of chlorine changes from +5 (in NaClO3) to +7 (in NaClO4). This indicates that 2 electrons are involved in the oxidation process per molecule of NaClO4 formed, requiring 2 faradays of charge. Hence, 2 faradays produce 1 mole of NaClO4. Therefore, 3 faradays will produce 3/2 = 1.5 moles of NaClO4. The other options are incorrect as they do not accurately reflect the stoichiometry based on the change in oxidation state.
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