This morning I took my three children to an internet cafe. Jay used the internet for 37 minutes and was charged $17.40, whilst Kay's 56 minutes cost $20.25, and Harry had to pay $19.05 for the 48 minutes that he spent online. Which of the following formulae does this cafe use to charge for its internet facilities?
Correct answer: D. $11.85 + $0.15 per minute
- A. $4.65 + $0.30 per minute
- B. $8.15 + $0.25 per minute
- C. $9.05 + $0.20 per minute
- D. $11.85 + $0.15 per minute
Explanation
To determine which formula the cafe uses to charge for its internet facilities, we can analyze the given information.Let's consider Jay's charges:Jay used the internet for 37 minutes and was charged $17.40.If we assume the formula for Jay's charges is A + (B x no. of minutes), we can set up an equation:$17.40 = A + 37BNow, let's consider Kay's charges:Kay used the internet for 56 minutes and was charged $20.25.If we assume the formula for Kay's charges is A + (B x no. of minutes), we can set up an equation:$20.25= A + 56BNext, let's consider Harry's charges:Harry used the internet for 48 minutes and was charged $19.05.If we assume the formula for Harry's charges is A + (B x no. of minutes), we can set up an equation:$19.05 = A + 48BBy solving any two of these equations simultaneously, we can find A (the fixed charge for access to internet) and B (the charge per minute).Subtracting Harry's equation from Kay's equation:$20.25 - $19.05 = 56B - 48B$1.2 = 8BB = $1.2/8B = $0.15Now we can substitute the value of B into any equation and solve it for A.Using Jay's equation:$17.40 = A + 37($0.15)$17.40 = A + $5.55A = $17.40 - $5.55 A = $11.85Based on the calculations, A (the fixed charge for access to internet) is $11.85, and B (the charge per minute) is $0.15. Hence, the correct formula for the cafe's internet charges is option D) $11.85 + $0.15 per minute.
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