The weight of 350 ml of a diatomic gas at 0°C and 2 atm pressure is 1 g. The weight of one atom is (N is the Avogadro's number):
Correct answer: B. 32 N
- A. 16/N
- B. 32 N
- C. 16 N
- D. 12 N
Explanation
Following is the solution to this question:
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Mole calculations connect mass, number of particles and Avogadro's number, while balanced equations provide the mole ratios used in stoichiometry. Questions cover limiting and excess reactants, theoretical yield and percentage yield, including identifying which reactant is consumed first and comparing the actual product with the maximum possible product.
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